I would do it a bit different. The wall with the urinal would have two stalls with stools. Two washing areas on the opposite wall along with a storage closet for the necessaries. But yours looks great. I did a part time job in a little shop the had only one bathroom with two toilets for both sexes. The owner remove the seat on one and fasten the seat down on the other.
The first place I worked, I was 18, The room have a toilet and sink. I tried to keep it clean. Others did not.
The office and restroom look fantastically real!!! One look at the restroom and I had to go, LOL. Joe
Yes.. I thought about it but really it was just one partition I had to take out and the radiator. It looks so much better now
If it were me, I would move the toilet and privacy partition both to the right, and get rid of the privacy partition between the sink and urinal. I have never seen a setup like that in the men's toilets at a bowling alley. Rick Jesionowski
Two points .… This is the upstairs office bathroom. Second point … I've never been in a men's toilet anywhere
I'm re-doing a side wall. I was having too much trouble with it. A little redesign and it will be perfect.
It is more complicated than just aim. If you look at the point where where the fluid leaves the edge of the channel, then the force F" role="presentation">F acting in the direction is: F=(γwa−γwt)ℓ" role="presentation">F=(γwa−γwt)ℓ where the length ℓ=l+2d" role="presentation">ℓ=l+2d A positive value of this force means the fluid is being pulled back into the channel. The force will normally be positive because the fluid/air interfacial tension is greater than the fluid chanel interfacial tension. That's why fluid dribbles back toward your feet. So far so good. Now, if this force is great enough to bring the fluid stream to a stop the fluid will dribble down the edge, while if the force larger than this the fluid will flow cleanly off. This is obviously an approximation because it's possible that the bottom of the fluid stream may slow and dribble while to top flows cleanly, but let's go with this and see where it gets us. We'll use the fact that force is equal to rate of change of momentum. The momentum of the fluid flowing off the edge in one second is simply: p=ρvA×v" role="presentation">p=ρvA×v because A=ld" role="presentation">A=ld is the area of the channel, and the velocity v" role="presentation">v is the length that flows in one second so vA" role="presentation">vA is the volume and therefore ρvA" role="presentation">ρvA the mass. So, if the fluid comes to a stop at the edge the rate of change of momentum is p" role="presentation">p , and therefore we will get dribbling when: (γwa−γwt)ℓ>ρAv2" role="presentation">(γwa−γwt)ℓ>ρAv2 or since the velocity is the only thing we can easily vary, we get dribbling when: v<(γwa−γwt)ℓρA" role="presentation">v<(γwa−γwt)ℓρA‾‾‾‾‾‾‾‾‾‾‾‾√ You can now immediately see why the fluid/channel interfacial tension matters. Remember γwt" role="presentation">γwt is normally less than γwa" role="presentation">γwa, but if we hydrophobe the channel surface we make γwt" role="presentation">γwt bigger. If we can make it big enough to equal the fluid/air interfacial tension, so γwa−γwt=0" role="presentation">γwa−γwt=0 then our equation becomes: v<zero×ℓρA" role="presentation">v<zero×ℓρA‾‾‾‾‾‾‾‾‾√
